NEW ORLEANS — New Orleans Saints defensive end Will Smith has signed a contract extension that will make him one of the NFL's highest-paid defensive players.

Smith signed a six-year deal worth about $70 million, according to a person familiar with the deal who requested anonymity because the terms had not been made public.

The deal makes Smith the NFL's third highest-paid defensive end, behind Kansas City's Jared Allen and Indianapolis' Dwight Freeney.

Smith made the Pro Bowl in 2006 and his seven sacks in 2007 led the Saints. He also was among team leaders in tackles with 66.

The Saints had no comment on the deal.

Smith, who received about $20 million in bonuses when he signed as a first-round draft choice out of Ohio State in 2004, was expected to earn between $1.8 million and $3 million next season, depending on performance incentives. The new contract will pay him more in 2008 but details were not immediately available.

Smith had been dissatisfied with his contract — which paled in comparison to the league's top defensive ends. Freeney is paid close to $12 million a year.

Last year, the Saints signed defensive end Charles Grant to a seven-year contract extension worth as much as $63 million if he reaches all incentives.

Smith has arguably outperformed Grant in recent years. He had 26 sacks over the past three seasons, compared to 11 for Grant.

"The Saints really stepped up," said Smith's agent, Joel Segal. "It was a long negotiation and a great deal for both Will and the Saints."

Smith skipped much of the Saints' offseason training program because of displeasure with his contract, but participated in a mandatory minicamp and remained in New Orleans afterward. He also worked out with the team during its final two weeks of organized team activities, which are voluntary.

"He'll be able to show up for training camp now with nothing on his mind but getting ready for the season and the Super Bowl," Segal said.